Question

If a,b,c in G.P,then a-b/b-c is equal to​

Answer 1

Step-by-step explanation:

a, b, c are in GP

let 'r' be the common ratio

1st term = a

2nd term = ar = b

3rd term = a${r}^{2} = c$

$\frac{(a - b)}{(b - c)} = \frac{a - ar}{ar - a {r}^{2} } = \frac{a(1 - r)}{ar(1 - r)}$

$\frac{(a - b)}{(b - c)} = \frac{1}{r}$