Question

If a+b+c is 5. ab+bc+ca is 10
Prove that a³+b³+c³-3abc=-25
Please answer this

Answer 1

Answer:

Step-by-step explanation:

a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)

a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-(ab+bc+ca))

-25=(5)(a^2+b^2+c^2-(10))

-25/5=a^2+b^2+c^2-10

-5=a^2+b^2+c^2-10

-5+10=a^2+b^2+c^2

a^2+b^2+c^2=5