if a + b + C is equal to 12 and a square + b square + c square is equal to 64 then a b + bc+ca is equal to what
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Given ,
a+b+c = 12
a square + b square + c square = 64
now,
we know that ,
a+b+c whole square = a square + b square +c square +2ab +2bc +2ca
12 square =64+2(ab+bc+ca)
144=64+2(ab+bc+ca)
144 - 64 = 2(ab+bc+ca)
ab+bc+ca = 80 ÷ 2
ab+bc+ca = 40
therefore, hence solved .
a+b+c = 12
a square + b square + c square = 64
now,
we know that ,
a+b+c whole square = a square + b square +c square +2ab +2bc +2ca
12 square =64+2(ab+bc+ca)
144=64+2(ab+bc+ca)
144 - 64 = 2(ab+bc+ca)
ab+bc+ca = 80 ÷ 2
ab+bc+ca = 40
therefore, hence solved .
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