if a + b + c is equal to 270 degree then find the value of cos 2A + cos 2 b + cos2c
chiragverma:
in u r question there is cos Square A or cos2A?
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A+B+C=270
A+B=270-C
C=270-(A+B)
cos2A+cos2B+cos2C
= 2 cos(2A+2B/2)cos(2A-2B/2)+cos2C
=2cos(A+B)cos(A-B)+ cos2C
=2cos(270-C) cos(A-B)+ cos2C
=-2sinC cos(A-B)+ cos2C
= - 2sinC cos(A-B)+1-2sin²C
=1-2sinC [ cos ( A- B) + sinC ]
=1-2 SinC [ cos( A-B) + sin( 270-(A+B) ]
=1- 2 SinC [ cos( A-B) - cos( A+ B) ]
= 1 -2 sinC [2 sinAsinB]
=1-4 SinAsinBsinC
A+B=270-C
C=270-(A+B)
cos2A+cos2B+cos2C
= 2 cos(2A+2B/2)cos(2A-2B/2)+cos2C
=2cos(A+B)cos(A-B)+ cos2C
=2cos(270-C) cos(A-B)+ cos2C
=-2sinC cos(A-B)+ cos2C
= - 2sinC cos(A-B)+1-2sin²C
=1-2sinC [ cos ( A- B) + sinC ]
=1-2 SinC [ cos( A-B) + sin( 270-(A+B) ]
=1- 2 SinC [ cos( A-B) - cos( A+ B) ]
= 1 -2 sinC [2 sinAsinB]
=1-4 SinAsinBsinC
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