If a + b + C is equal to 6 and a b + BC + ca is equals to 11 find the value of a cube plus b cube plus c cube - 3abc
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Step-by-step explanation:
a + b + c = 6 ----(1)
वर्ग करने पर
(a + b + c )² = 36
a²+b²+c²+2(ab+bc+ac) = 36
a² + b² + c² + 22 = 36
a² + b² + c² = 14 ------(2)
a³ + b³ + c³ - 3abc
=(a+b+c)(a² + b² + c² - ab - bc - ac)
=(a+b+c)(a² + b² + c² -(ab+bc+ac))
= 6(14 - 11)
= 6*3 = 18
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