if a + b + c is equal to zero then a^3 + b^3 + c^3 is equal to
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Now, a3+b3 + c3 = (a+ b + c) (a2 + b2 + c2 – ab – be – ca) + 3abc
[using identity, a3+b3 + c3 – 3 abc = (a + b + c)(a2+b2+c2 –ab–bc-ca)] = 0 + 3abc [∴ a + b + c = 0]
a3+b3 + c3 = 3abc.
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Answer:
a+b+c=0 ( given)
to find ( a^3 + b^3 + c^3 )
Now, a+b+c=0
therefore, a^3 + b^3 + c^3= 3(a)(b)(c)
or a^3 + b^3 + c^3= 3abc
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