If a+b+c is not equal to 0 then prove a^3+b^3+c^3=3abc,only when a=b=c
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Answered by
19
heya mate !! how's gojng on ? here is your answer !!+!
I think
It’s not required that a=b=c for this identity to hold true.
As we know
a3 +b3 + c3 – 3abc = (a+b+c) (a2 + b2 + c2 – ab – bc – ca)
If a+b+c = 0 , then your given statement is true
Also if a=b=c then either all are positive numbers or all should be negative numbers which cannot sum upto zero.
hope that helps !!
⭐ tysm - himanshu Jha ✌
I think
It’s not required that a=b=c for this identity to hold true.
As we know
a3 +b3 + c3 – 3abc = (a+b+c) (a2 + b2 + c2 – ab – bc – ca)
If a+b+c = 0 , then your given statement is true
Also if a=b=c then either all are positive numbers or all should be negative numbers which cannot sum upto zero.
hope that helps !!
⭐ tysm - himanshu Jha ✌
Answered by
40
Answer:
Step-by-step explanation:
As given a=b=c, then we can replace b,c by a as a=b, a=c
So,
a^3+b^3+c^3 = 3(a)(b)(c)
a^3+a^3+a^3 = 3(a)(a)(a)
3a^3 = 3a^3
LHS = RHS
Hence, proved.....
Hope it helps....
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