Math, asked by adityadubey2004, 1 year ago

If a+b+c is not equal to 0 then prove a^3+b^3+c^3=3abc,only when a=b=c

Answers

Answered by Anonymous
19
heya mate !! how's gojng on ? here is your answer !!+!

I think

It’s not required that a=b=c for this identity to hold true.

As we know
a3 +b3 + c3 – 3abc = (a+b+c) (a2 + b2 + c2 – ab – bc – ca)
If a+b+c = 0 , then your given statement is true
Also if a=b=c then either all are positive numbers or all should be negative numbers which cannot sum upto zero.

hope that helps !!

⭐ tysm - himanshu Jha ✌
Answered by shirsendu26122005
40

Answer:

Step-by-step explanation:

As given a=b=c, then we can replace b,c by a as a=b, a=c

So,

a^3+b^3+c^3 = 3(a)(b)(c)

a^3+a^3+a^3 = 3(a)(a)(a)

3a^3 = 3a^3

LHS = RHS

Hence, proved.....

Hope it helps....

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