Question

If a+b+c=m and 1/a+1/b+1/c=0 then average of a^2, b^2 and c^2 is?
​

Answer 1

Answer:

 =  

3

9M

2

​

=3M

2

Step-by-step explanation:

Given,  

3

a+b+c

​

=M⇒a+b+c=3M

Now, (a+b+c)

2

=a

2

+b

2

+c

2

+2(ab+bc+ca)

⇒(3M)

2

=a

2

+b

2

+c

2

+0⇒a

2

+b

2

+c

2

=9M

2

Average of a

2

,b

2

,c

2

=

3

a

2

+b

2

+c

2

​