If A + B + C =pi and cos A = cos B cos C, then tan A =
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Step-by-step explanation:
Given A+B+C=π⟹A=π−(B+C)
And also given cosA=cosBcosC
⟹cos(π−(B+C))=cosBcosC
⟹−cosBcosC+sinBsinC=cosBcosC
⟹sinBsinC=2cosBcosC
⟹tanBtanC=2
Answered by
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Step-by-step explanation:
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