Question

If A + B + C = pi, prove that (i) tanA + tanB + tanC = tanA tanB tanC

Answer 1

A+B+C=π or, A+B=π-C or, tan(A+B)=tan(π-C) or, tanA+tanB/1-tanAtanB= -tanC or, tanA + tanB= -tanC + tanAtanBtanC or, tanA+tanB+tanC=tanA tanB tanC. Hope it helps please mark as branliest.