If a, b, c € R show that the roots of the following equation (a-b)x^2 + (b+c-a)x -c=0 are rational.
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Answer:
3x
2
−2x(a+b+c)+(ab+bc+ca)=0
Let D be the discriminant
D=4(a+b+c)
2
−12(ab+bc+ca)
=4[(a+b+c)
2
−3(ab+bc+ca)]
=2[2a
2
+2b
2
+2c
2
−2ab−2bc−2ca]
=2[(a−b)
2
+(b−c)
2
+(c−a)
2
]
If D=0, then
(a−b)
2
+(b−c)
2
+(c−a)
2
=0
⇒a−b=0;b=c;c=a
or a=b=c
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