Question

If a=(b-c)secx
then tanx=​

Answer 1

Answer:

Here, secx = a/(b-c)

so, tanx = root of[sec^2 x - 1]

= root of[{a/(b-c)}^2 -1]

= root of{a^2-(b-c)^2}/(b-a) ..... answer.

Thank you!!