if a+b=c,then show that b^2+ac=c^2-ab
abhi569:
i think
it should be (-ac) in last ..........may be
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Assume
a = 2, b = -1 , c = 1
a + b = c => 2 + (-1) = 1
b^2 + ac = c^2 - ab
=> (-1)^2 + 2*1 = 1^2 - 2(-1)
=> 3 = 3.
a = 2, b = -1 , c = 1
a + b = c => 2 + (-1) = 1
b^2 + ac = c^2 - ab
=> (-1)^2 + 2*1 = 1^2 - 2(-1)
=> 3 = 3.
it is a right answer
or not
or Not
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