if A +B = C then write the value of tan A tan B Tan c
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4
A + B = C
taking function of tan both sides ,
=> tan (a+b) = tan c
we know that , tan(a+b) =
(tan a + tan b ) / (1 - tan a tan b )
=>( tan a + tan b) / (1 - tan a tan b )= tan c
=> cross multiply , we get ,
=> tan a + tan b = tan c - tan a tan b tan c
=> tan a tan b tan c = tan c - tan a - tan b
Answered by
3
Given that :
A+B = C
On taking tan both the side :
tan(A+B) = tanC
As we know that : tan(A+B) = tanA+tanB/(1-tanAtanB)
=> tanA+tanB/1-tanAtanB = tanC
=> tanA+tanB = tanC-tanAtanBtanC
=> tanAtanBtanC = tanC-tanB-tanA
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