Question

if a + b + c = to 6 then find the value of (2-b)³ +( 2- b)³ + (2-c)³-3(2-a) (2-b) (2-c)

Answer 1

if x + y + z = 0 .
then x^3+y^3+z^3=3xyz.

Here, x = 2-a
y =2-b
z=2-c
and a+b+c=6
value of x^3+y^3+z^3-3xyz= 3xyz-3xyz=0.