if a, b, can are in AP then a-b÷b-c=
A) 1
B) a÷b
C) b÷c
D) c÷a
Answers
Answered by
4
a, b, c are in AP
So, the common difference is constant
Term 3 - Term 2 = Term 2 - Term 1
b-a = c- b
=> (b-a) / (c-b) = 1
=> - (a-b) / - (b-c) = 1
=> (a-b) / (b-c) = 1
So, the common difference is constant
Term 3 - Term 2 = Term 2 - Term 1
b-a = c- b
=> (b-a) / (c-b) = 1
=> - (a-b) / - (b-c) = 1
=> (a-b) / (b-c) = 1
Answered by
0
a)1 is the answer
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