Question

if a'b+cd'=0 then prove ab+c'(a'+d')=ab+bd+b'd'+a'c'd​

Answer 1

Explanation:

Down vote

A truth table shows that left-hand-side and righ-hand-side are in fact equivalent if the constraint is fulfilled (indicated by background color):

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Answer 2

Concept:

A Truth Table is a table that is used to represent a logic gate function's boolean expression.

Given:

$a'b+cd'=0$.

Prove:

$ab+c'(a'+d')=ab+bd+b'd'+a'c'd$.

Solution:

Each possible input combination to the gate or circuit is shown in a logic gate truth table, along with the subsequent output based on the combination of these input(s).

In the following truth table whenever $a'b+cd'=0$,

$ab+c'(a'+d')=ab+bd+b'd'+a'c'd$.

Hence proved.