if a+ b+ cis equal to 6 and a square + b square + c square is equal to 14 , find ab + bc + ca
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a+b+c = 6
a^2 + b^2 + c^2 = 14
ab+bc+ca = a(b+c)+ bc
a= 1
b= 2
c=3
1^2 + 2^2 + 3^2 = 14
ab+ac+bc= 2+3+6 = 11
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Answer:
(a+b+c)²=a²+b²+c²+2ab+2bc+2ac
(6)²=14+2ab+2bc+2ac
36-14=2(ab+bc+ca)
12/2 =ab+bc+ca
ab+bc+ca=6
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