if A={b,d,e,g,h},and B={a,e,c,h},verify that n(A-B)=n(A)-n(A intersection B)
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Step-by-step explanation:
A={b,d,e,g,h},and
B={a,e,c,h},
n(A) = 5
n(B) = 4
A-B= {B, d, g}
n(A-B) = 3
AnB= {e, h}
n(AnB) = 2
LHS= n(A-B) = 3
RHS = n(A)-n(A intersection B)
= 5-2
=3
LHS=RHS
Hence verified
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