If a + b equals to 11 a square + b square equal to 61 find a cube plus b cube
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Given: a+b=11.................(1)
And a^2+b^2= 61...........(2)
To find: a^3+b^3=?
Now we know,
(a^3+b^3)=(a+b) (a^2-ab+b^2).............(3)
From (1),
(a+b)^2= 11^2
Or,a^2+2ab+b^2=121
Or, (a^2+b^2)+2ab=121
Or, 61+2ab=121
Or, 2ab= 121-61
Or,2ab= 60
Hence, ab= 30
Now, using this in equation (3), we get
(a^3+b^3) = (a+b)(a^2+b^2-ab)
= 11 (61-30)
= 11*31
=341.
This is the required answer.
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