Question

If a-b is 4 and a+b is 6 find 1) a²+b², 2) ab​

Answer 1

Answer:

${ \large{ \pmb{ \sf{★ Given... }}}}$

a - b = 4 , a + b = 6

${ \large{ \pmb{ \sf{★Find... }}}}$

(i) a² + b² (ii) ab

${ \large{ \pmb{ \sf{★Solution... }}}}$

First we have to find values of a and b by using elimination method.

a - b = 4____(1)

a + b = 6____(2)

From (1) & (2) :

: ➙ a - b + a + b = 4 + 6

: ➙ 2a = 10

: ➙ a = 10/2

: ➙ a = 5

By substituting value of a in eq(1),

➠ a - b = 4

➠ 5 - b = 4

➠ - b = 4 - 5

➠ b = 1

Therefore, a = 5 and b = 1

(i) a² + b² :

$: \: \: { \to{{5}^{2} + {1}^{2} }} \\ \\ : \: \: { \to{25 + 1}} \\ \\ : \: \: { \to \bf{ {a}^{2} + {b}^{2} = 26}}$

(ii) ab :

$\: : \: \: { \to{5 \times 1}} \\ \\ : \: \: { \to \bf{ab = 5}}$

${ \large{ \pmb{ \sf{★Final \: Answer... }}}}$

(i) a² + b² = 26

(ii) ab = 5

Answer 2

Step-by-step explanation:

Answer:

{ \large{ \pmb{ \sf{★ Given... }}}}

★Given...

★Given...

a - b = 4 , a + b = 6

{ \large{ \pmb{ \sf{★Find... }}}}

★Find...

★Find...

(i) a² + b² (ii) ab

{ \large{ \pmb{ \sf{★Solution... }}}}

★Solution...

★Solution...

First we have to find values of a and b by using elimination method.

a - b = 4____(1)

a + b = 6____(2)

From (1) & (2) :

: ➙ a - b + a + b = 4 + 6

: ➙ 2a = 10

: ➙ a = 10/2

: ➙ a = 5

By substituting value of a in eq(1),

➠ a - b = 4

➠ 5 - b = 4

➠ - b = 4 - 5

➠ b = 1

Therefore, a = 5 and b = 1

hope this helps you