If a-b is 6 and ab is 20 then find the value of a cube - b cube
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So
According to question find
A^3-b^3=(a-b)(a^2+b^2+ab)
Putt the given value
So
A^3-b^3=(6)(a^2+b^2+20)
A^3-b^3=6a^2+6b^2+120
.
.i hope this will help u
BY DEVANSH
According to question find
A^3-b^3=(a-b)(a^2+b^2+ab)
Putt the given value
So
A^3-b^3=(6)(a^2+b^2+20)
A^3-b^3=6a^2+6b^2+120
.
.i hope this will help u
BY DEVANSH
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