Question

if a-b is 7 and ab = 18 ; find a square plus b square ​

Answer 1

$\huge{\underline{\underline{\pink{Ans}\red{wer:-}}}}$

$\bold{The \ value \ of \ a^{2}+b^{2} \ is \ 13.}$

$\bold\blue{Explanation:}$

$\bold{Identity:-}$

$\bold{a^{2}+b^{2}=(a-b)^{2}+2ab}$

$\huge\orange{Given:-}$

$\bold{=>a-b=7}$

$\bold{=>ab=18}$

$\bold\pink{To \ find:}$

$\bold{Value \ of \ a^{2}+b^{2}}$

$\bold\green{\underline{\underline{Solution:}}}$

$\bold{According \ to \ identity}$

$\bold{a^{2}+b^{2}=(a-b)^{2}+2ab}$

$\bold{=>a^{2}+b^{2}=7^{2}-2(18)}$

$\bold{=>a^{2}+b^{2}=49-36}$

$\bold{=>a^{2}+b^{2}=13}$

$\bold\purple{\tt{\therefore{The \ value \ of \ a^{2}+b^{2} \ is \ 13.}}}$