Question

if (a-b) is 9 more than (c+d) and (a+b) is 3 less than (c-d) ,then (a-c) is ?

Answer 1

As given: the value of (a-b) is 9 greater than the value of (c+d)

∴ (a-b) = (c+d) + 9 ------ (1)

Now the value of (a+b) is 3 lesser than the value of (c-d)

∴ (a+b) =(c-d) - 3 --------(2)

Adding both we get

$\begin{gathered}a-b+a+b = c+d+9+c-d-3\\\\\Rightarrow2a= 2c+6\\\\\Rightarrow2a-2c=6\\\\\Rightarrow2(a-c)=6\\\\\Rightarrow(a-c)= \dfrac{6}{2} =3\end{gathered}$

Hence, the value of (a-c) is 3