Question

If a b is an operation for integers a and b such that a b = a × b + b *6-2 x a x (b), then find
(-8) (-2)​

Answer 1

Answer:

Given, a ×b=a×b+(a×a+b×b)

So.we put a=(−3) and b=(−5)

{−3)∗(−5)=(−3)×(−5)+[(−3)×(−3)+(−5)×(−5)]

=15+(9+25)=15+34=49

Similarly, a=−6,b=2

(−6)∗2=(−6)×2+[(−6)×(−6)+2×2]=−12+(36+4)

=−12+40=28