Math, asked by sarbani25, 9 months ago

if a + b is equal to 10 and a b is equal to 16 find the value of a square minus a b + b square​

Answers

Answered by sujatasultana239
0

Answer:

52

Step-by-step explanation:

given, a+b = 10

             ab = 16

now,

a^2 - ab + b^2 = (a+b)^2 - 3ab

                        = 10^2 - 3* 16

                        = 100 - 48

                        = 52

Answered by lhh
1

Answer:

Given : a + b = 10 ............(1)

and ab = 16 .....................(2)

It is known that,

(a + b)² = a² + 2ab + b²

Now, substituting the values of (1) and (2) in the above, we get.

⇒ (10)² = a² + 2*(16) + b²

⇒ 100 = a² + 32 + b²

⇒ a² + b² = 100 - 32

⇒ a² + b² = 68 .................(3)

Now, substituting the value of a² + b² = 68 in a² - ab + b²

⇒ 68 - 16 (as ab = 16)

⇒ 52

And, substituting the value of a² + b² = 68 in a² + ab + b²

⇒ 68 + 16

⇒ 84

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