Question

if a + b is equal to 2, prove that a³+6ap+p³-8=0​

Answer 1

Step-by-step explanation:

P = 2-a or a+p = 2

a³ + 6ap+p³ -8 = (a³+p³) + 6ap - 8 = (a+p)(a²+p²-ap) + 6ap - 8

= 2(a²+p²-ap) + 6ap - 8 = 2(a²+p²-ap + 3ap) - 8 = 2(a+p)² - 8 = 2x2² - 8 = 0

Answer 2

Answer:

using formula of ,

$(a + b) {}^{3} = {a}^{3} + {b}^{3} + 3ab(a + b)$

hope it helps you ✔