Math, asked by utkarsh4224, 1 year ago

if a + b is equal to 5 ,ab equal to six a is greater then find the value of 4(a^2-b^2)-a^3b^3​

Answers

Answered by Anonymous
1

Answer:

we are given a+b=5

ab=6

4(a^2-b^2) -a^3b^3

= 4(a-b)^2-(ab)^3

we know, (a-b) ^2= a^2-2ab+b^2

4(a^2+b^2-2ab) -(ab) ^3

substituting value,

4{(5) ^2-2(6) }-(6) ^3

=4×{25-12)}-216

=4×13-216

=52-216

=-160

ans is (-160)

Similar questions