Math, asked by nathg6610, 8 months ago

if a + b is equal to 8 and a b is equal to -1 evaluate a square + b square​

Answers

Answered by peehugupta412
3

Answer:

a+b=8

ab=-1

BY APPLYING IDENTITY,

(a+b)square= a^2+b^2+2(ab)

(8) square= a square+b square + 2(-1)

64= a square+b square+ (-2)

64+2= a square+b square

66= a square+b square

Answered by beherags
1

Answer:

a + b = 8

ab = -1

(a +b)^2 = a^2 + b^2 + 2ab

8^2 = a^2 + b^2 + 2 (-1)

64 = a^2 + b^2 + (-2)

64-2 = a^2 + b^2

62 = a^2 + b^2

So, 62 is your answer

Step-by-step explanation:

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