if a + b is equal to 90 degree prove that 1 + 10 a upon 10 b is equal to 10 square A minus sec square B
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Step-by-step explanation:
Given, LHS = root tan a tan b + tan a cot b/sin a sec b - sin^2 b/cos^2 a = root tan a tan(90-a) + tan a cot(90-a)/sin a sec(90-a) - sin^2(90-a)/cos^2 a …
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