If (a,b) is mid point of line segment joining the points A(10,-6), B(k,4) and a-2b =18,then find the value of k and the distance AB.
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Since (a,b) is mid point so
(a,b) = { (10+k)/2 , (-6+4)/2}
here,
a = (10+k)/2
and
b= -2/2 = -1
put a=(10-k)/2 and b=-5 in a-2b=18
(10+k)/2-2 (-1) =18
10+k+2=36
k= 36-12 = 24
now
AB =
= 14×10
= 140
hope it helps you
(a,b) = { (10+k)/2 , (-6+4)/2}
here,
a = (10+k)/2
and
b= -2/2 = -1
put a=(10-k)/2 and b=-5 in a-2b=18
(10+k)/2-2 (-1) =18
10+k+2=36
k= 36-12 = 24
now
AB =
= 14×10
= 140
hope it helps you
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