If a^b means a to the poer of
b.then f(x)=ax^4-bx^2+x+5 and f(-3)=2,then f(3)?
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The answer in eight because the values of a, b, c remain constant and also the value of x^4 and x^2 also remain constant irrespective of the negative or positive values of x
Only the value of x changes from -3 to 3
I.e. 6 is added and it will be added to 2
Only the value of x changes from -3 to 3
I.e. 6 is added and it will be added to 2
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