if (a/b)^p-2=(b/a)^p-4 then p is equal to. options, 3, 1/2, 2, 7/2
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Solution:
/* By Exponential laws,
i )(x/y)ⁿ = (y/x)^-n
i )(x/y)ⁿ = (y/x)^-nii ) If a^m = a^n then m=n */
Now ,
(a/b)^p-2 = (b/a)^p-4
=> (a/b)^p-2 = (a/b)^[-(p-4)]
=> (a/b)^p-2 = (a/b)^(-p+4)
=> p-2 = -p+4
=> p+p = 4+2
=> 2p = 6
=> p = 6/2
=> p = 3
Therefore,
p=3
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