If a b parallel angle bac equal to 35 degree and angle c d equal 53 degree find angle dce
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Prove “if two lines intersect each other, then the vertically opposite angles are equal.”
Let AB and CD be two lines intersecting at O. Ray OE bisects ∠AOB and OF is the ray opposite to OE.
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Solution:
It is given that AB∥DE. Therefore, ∠BAC=∠DEC (Alternate Interior Angles)
∠BAC=35° (Given)
Therefore, ∠DEC=35°
In ∆DCE, we have
∠DEC+∠CDE+∠DCE=180° (Sum of three angles of a triangle =180°)
⇒35°+53°+∠DCE=180°
⇒∠DCE=180°−35°−53°=92°
I hope, this will help you.☺
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