Question

if A+B=pi/3 and cosA + cosB=1, then

cos(A-B)=1/3

। cosA-cosB । =root(2/3)

cos(A-B)= -1/3

। cosA -cosB । = 1/2root3​​​

where ​। is modulus

Answer 1

x = 2 pi n+pi, n element Z 
Reduce[-Cos[Pi/6 - x]^3 + Cos[Pi/6 + x]^3 + Sin[x]^3 == (-3 Sin[3 x])/4, x] 
{{x == Pi + 2 Pi C[1], Element[C[1], Integers]}}

Answer 2

Your search - if A+B=pi/3 and cosA + cosB=1, then cos(A-B)=1/3 । cosA-cosB । =root(2/3) cos(A-B)= -1/3 । cosA -cosB । = 1/2root3​​​ where ​। is modulus - did not match any documents. Suggestions: Make sure that all words are spelled correctly. Try different keywords. Try more general keywords.