if a+b= pi/4 , prove that (1+tan A) (1+tanB) = 2
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Hello Mate,
Here is your answer,
Given:
a + b = 45°
To find:
(1+tanA) (1+tanB) = 2
Solution:
Apply tan on both sides we get,
Tan(a + b) = tan(45°)
TanA + TanB/1- tanA tanB = 1
TanA + tanB = 1 - tanA.tanB
TanA + tanB + tanA.tanB = 1
Add one on both sides,
1 + tanA + tanB + tanA.tanB = 1 + 1
Take (1+ tanA) common we get,
(1 + tanA) (1 + tanB) = 2
Hence proved
Hope it helps:)
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