Question

if a,b qre the zero of the POLYMIAL f(x) x²+5x+8,then a+b​

Answer 1

$Given \: a,b \:are \: Zeroes \:of \:the$

$polynomial \: f(x) = x^{2} + 5x + 8$

$\red{ Sum \:of \:the \: zeroes }$

$\blue{ = \frac{- x \: coefficient }{x^{2} \: coefficient }}$

$\implies a + b = \frac{-5}{1}$

$\green { = -5 }$

Therefore.,

$\red{ Sum \:of \:the \: zeroes }\green { = -5}$

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Answer 2

Answer:

5

−5-5

8

−8-8

Answer : 

B

Solution : 

For ax2+bx+cax2+bx+c, we have α+β=−ba.α+β=-ba. 

For x2+5x+8x2+5x+8, we have α+β=−5.