Question

If A =B + $\frac{C}{D+E}$, the dimensions of B and C are LT-¹ and M°LT° respectively. Find the dimensions of A, D and E

Answer 1

sorry for the long delay.

The answer is in the above attachment...

Hope it helps....

Regards;

Leukonov/Olegion

Answer 2

Required Answer :

Here,

Dimensions of A = Dimensions of B = Dimensions of $\dfrac{c}{D+E}$

⇒ [A] = [B] = [ $\dfrac{c}{D+E}$ ]

[A] = [B] = LT power 1 = [ $\dfrac{c}{D+E}$ ]

⇒$\dfrac{[c]}{[D+E]}$ = $\dfrac{[c]}{[D]}$ = LT power 1

⇒$\dfrac{M°LT°}{[D]}$ = LT power ¹

⇒ [D] = T¹ = [E]

[A] = M°LT power -1

[D] = M°L°T¹

[E] = M°L°T¹

Thank you for asking such an useful Question Mate...