Question

if a = -b then find the value of (a-b)²​

Answer 1

Answer:   $2b^{2}$

Step-by-step explanation:

Given a = -b

(a-b)²​= $a^{2} -2ab +b^{2}$

        = $-b^{2}$ - 2 × -b × b + $b^{2}$

        = $-b^{2} +2b^{2} +b^{2}$

        = $3b^{2} - b^{2}$

        = $2b^{2}$

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Answer 2

Answer:    = $2b^{2}$  

Step-by-step explanation:

(a-b)²​=$(-b-b)^{2}$ = $-b^{2}$ - (2 × -b × b) + $b^{2}$

                         = $-b^{2}$ - (-$2b^{2}$ )  + $b^{2}$

                         =   - (-$2b^{2}$ )

                         = $2b^{2}$