If a"=b, then n√b =
Answers
Answer:
Let a be the first term and d be the common difference.
mth term of an A.P is begin mathsize 16px style 1 over straight m end style.
am = a + (m - 1)d
begin mathsize 16px style rightwards double arrow straight a space plus space md space minus space straight d space equals space 1 over straight n space space space.... space space left parenthesis straight i right parenthesis
straight n to the power of th space term space of space an space straight A. straight P space is space 1 over straight n.
straight a subscript straight n space equals space straight a space plus space left parenthesis straight n space minus 1 space right parenthesis straight d space
rightwards double arrow space straight a space plus space nd space minus space straight d space equals space 1 over straight m space space space space.... space space left parenthesis ii right parenthesis
Subtract space left parenthesis ii right parenthesis space from space left parenthesis straight i right parenthesis comma space we space get
straight d space equals space 1 over mn
Put space space straight d space equals 1 over mn space in space equation space left parenthesis straight i right parenthesis comma space we space get
straight a space equals 1 over mn
space space
To space find space mn to the power of th term colon
straight a subscript mn space equals space straight a space plus space left parenthesis mn space minus space 1 right parenthesis straight d space equals space 1 over mn plus space left parenthesis mn space space minus space 1 right parenthesis space 1 over mn space equals space 1 end style
Answered by Yasmeen Khan | 25th Mar, 2019, 11:23: AM
Step-by-step explanation:
Answer:
a+b]/2=[a^n+1+b ^n+1]/a^n+b^n
[a+b]/2=a^n*a+b^n*b/a^n+b^n (ax+y=ax*ay)
Then by cross multiplication we get
a^na+a^nb+b^na+b^nb=2a^na+2b^nb
a^nb+b^na=a^na+b^nb
a^nb-a^na=b^nb-b^na
a^n(b-a)=b^n(b-a)
a^n=b^n
It is only possible if n=0
Therefore, n=0
Step-by-step explanation:
#fake do dude