if (a/b)^x-1 = (b/a)x-3 then find x
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(a/b)x-1=(b/a)2x-8
(a/b)x-1=(a/b)-(2x-8)
(a/b)x-1=(a/b)-2x+8
x-1=-2x+8
x+2x=8+1
3x=9
x=9/3
x=3
(a/b)x-1=(a/b)-(2x-8)
(a/b)x-1=(a/b)-2x+8
x-1=-2x+8
x+2x=8+1
3x=9
x=9/3
x=3
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