Question

if a+b=x and ab=y then find the values of a and b​

Answer 1

Answer:

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Answer 2

$Given \: a + b = x \: --(1)$

$and \: ab = y\: --(2)$

$i) a-b = \pm \sqrt{ (a+b)^{2} - 4ab }$

$= \pm \sqrt{ x^{2} - 4y } \: --(3)$

/* Add Equations (1) and (3) ,we get */

$2a = x \pm \sqrt{ x^{2} - 4y }$

$\implies \green { a = \frac{x \pm \sqrt{ x^{2} - 4y }}{2}}$

/* Subtract equation(2) from equation (1),we get*/

$2b = x \mp \sqrt{ (a+b)^{2} - 4ab }$

$\implies\green { b = \frac{x \mp \sqrt{ x^{2} - 4y }}{2}}$

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