Question

If a,b,x are positive real numbers, then √a-1 b x√b-1 x√c-1a is equal to​

Answer 1

ANSWER

[(1+a)(1+b)(1+c)]  

7

>7  

7

a  

4

b  

4

c  

4

 

i.e.,(1+∑a+∑ab+abc)>7(abc)  

4/7

 

Since, AM>GM

a+b+c+≥3(abc)  

1/3

 

ab+bc+ac≥3(a  

2

b  

2

c  

2

)  

1/3

 

Hence,  

1+∑a+∑ab+abc≥1+3(abc)  

1/3

+3(abc)  

2/3

+abc1+∑a+∑ab+abc≥1+(abc)  

1/3

+(abc)  

1/3

+(abc)  

1/3

+(abc)  

2/3

+(abc)  

2/3

+(abc)  

2/3

+abc

So,  

LHS≥7[1(abc)  

1/3

(abc)  

1/3

(abc)  

1/3

(abc)  

2/3

(abc)  

2/3

(abc)  

2/3

(abc)]  

1/7

≥7[(abc)  

9/3

(abc)]  

1/7

 

≥7(abc)  

4/

Answer 2

Step-by-step explanation:

see the above attachment hope you understood mark me as brilliest