if a=b^x,b=c^y and c=a^z then find the value of xyz
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a=b^x
by taking log we get,
log a= log(b^x) {as, log (m^n)=n log m}
=x log b
or, x= (log a)/ (log b)
similarly, y=(log b)/(log c)
and z= (log c)/(log a)
thus,
xyz
=(log a× log b× log c)÷(log a×log b× log c)
=1
by taking log we get,
log a= log(b^x) {as, log (m^n)=n log m}
=x log b
or, x= (log a)/ (log b)
similarly, y=(log b)/(log c)
and z= (log c)/(log a)
thus,
xyz
=(log a× log b× log c)÷(log a×log b× log c)
=1
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