Question

If (a-b)x2 +(b-c)x + c-a=0
have equal
roots then show 2a = b+c.​

Answer 1

Answer:

don't know noooooooooooooooo

Step-by-step explanation:

Noooooooooooooooooooooo

Answer 2

Answer:

given

d = 0 (equal roots)

to prove -- 2a = b+c

proof --

d= 0 (given)

d = (b-c)^2 -4(a-b)(c-a)

0 = b^2 +c^2 -2bc -4ac +4a^2 +4bc - 4 ab

0 = (-2a)^2 +b^2 +c^2 2(-2a)b +2bc +2(-2a)c

by using formula {(a+b+c )^2= a^2+b^2+c^2+2ab +2bc +2ac }

0 = (-2a + b + c )^2

0 = (-2a + b + c )(-2a + b + c )

0 ×(-2a + b + c ). = (-2a + b + c )

0 = -2a + b + c

2a = b+c

hence proved

hope it will help you