Question

If a.b.y are zero of the cubic polynomialp(x)=6x^3+5x^2-3x+1 then find value of a^-1 + b^-1 + y^-1

Answer 1

hey this is ur answer
Given α,β & ɣ are the roots of the polynomials 6x3 + 3x2 - 5x + 1 = 0 then
α+β+ɣ  = -3/6 = -1/2
αβ+βɣ+αɣ = -5/6
αβɣ = -1/6
α-1 + β-1 + ɣ-1 = 1/α + 1/β + 1/ɣ = (αβ+βɣ+αɣ) / αβɣ = -5/6 / -1/6 = 5