Question

If a,b,y be the zeroes of the
polynomial p(x) such that
(a + B + y) = 3, (aß + By+ya) = -10
and aßy = -24 then p(x) =?
A
x3 + 3x2 - 10x + 24
B
x3 + 3x2 + 10x - 24
С
x3 – 3x2 – 10x + 24​

Answer 1

Step-by-step explanation:

Given -

◕ α + β + γ = 3

◕ αβ + βγ + γα = -10

◕ αβγ = -24

To Find -

➳ A cubic polynomial

Now,

As we know that :-

• α + β + γ = 3

⇝ -b/a = 3/1 .... (i)

And

• αβ + βγ + γα = -10

⇝c/a = -10/1 .... (ii)

And

• αβγ = -24

⇝ -d/a = -24/1 ..... (iii)

Now,

From (i), (ii) and (iii), we get :-

a = 1

b = -3

c = -10

d = 24

As we know that :-

For a cubic polynomial :-

• ax³ + bx² + cx + d

⇝(1)x³ + (-3)x² + (-10)x + (24)

⇝ x³ - 3x² - 10x + 24

Hence,

The cubic polynomial is x³ - 3x² - 10x + 24.

Therefore,

Option C is correct.

Answer 2

Step-by-step explanation:

hope its helpful