If a = b2 = c3, then the value of loga(abc) is
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1
Answer:
17/6
Step-by-step explanation:
Given
a=b²=c³
writing b and c in terms of a
b²=a
b=a½
c³=a
c=a⅓
asked to find
loga(abc)
substitute a,b,c
loga(aa½a⅓)
bases are equal add exponent
a¹+a¹+a½+a⅓
a^17/6
therefore
log(a)^17/6
17/6 log(a)
since loga=1
therefore
17/6
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