If a = b2x , b = c2y and c = a2z , show that 8xyz = 1
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Answered by
11
Answer:
proved 1=8xyz
Step-by-step explanation:
a=b2x
a=c2y*2x ( b=c2y)
a=a2z*2y*2x ( c=a2z )
a/a=2*2*2xyz
1=8xyz
Answered by
15
Step-by-step explanation:
a=b2x--->(1)
b=c2y--->(2)
c=a2z--->(3)
on doing(1)×(2)×(3)
=>abc=(b2x)(c2y)(a2z)
=>abc=8(abc)(xyz)
=>8xyz=abc/abc
therefore,8xyz=1
give a❤
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