Question

if a =b2X,b=c2y and c=a2z, show that 8xyz=1​

Answer 1

Answer:a=b2x--->(1)

b=c2y--->(2)

c=a2z--->(3)

on doing(1)×(2)×(3)

=>abc=(b2x)(c2y)(a2z)

=>abc=8(abc)(xyz)

=>8xyz=abc/abc

therefore,8xyz=1

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